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KPSC AE 2018: Specific Paper

Option 2 : 19 mm and 0.095

Highway and bridges 1

1357

10 Questions
20 Marks
12 Mins

__Concept:__

When the floor slabs (or roof slabs) transferring load to the wall do not bear on it for the full width of the wall, the vertical load transferred to will act eccentrically. Eccentric vertical loads or axial loads plus lateral loads on wall cause bending stresses in addition to axial stresses.

Figure shows a wall of thickness t, carrying axial load w_{1} and eccentric load W_{2} at eccentricity e, per unit length of wall. The resultant load W will have an eccentricity e’ which can be found by taking moments around the centroid of the section AB.

(W x e’)=(W_{1 }x 0 + W_{2 }x e)

e’= (W_{2} x e)/( W_{1}+ W_{2})

**Eccentricity ratio = (Equivalent Eccentricity)/thickness of wall**

__Calculation:__

Axial load (W_{1}) = 26 KN

Another load = 19 KN/m

Eccentricity = 45 mm

Thickness of wall = 200 mm

Equivalent eccentricity = e’= (19 × 45)/(19 + 26) = 19 mm

Eccentricity ratio = (Equivalent Ec centricity)/thickness of wall = 19/200 = 0.095